/*******************************************************************************
 * Copyright (c) 2010 Haifeng Li
 *   
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *  
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 *******************************************************************************/
package smile.interpolation;

import smile.math.Math;

/**
 * Shepard interplation is a special case of normalized radial basis function
 * interpolation if the function φ(r) goes to infinity as r → 0, and is
 * finite for r > 0. In this case, the weights wi are just equal to
 * the respective function values yi. So we need not solve linear
 * equations and thus it works for very large N.
 * 

* An example of such φ is φ(r) = r-p with (typically) * 1 < p ≤ 3. *

* Shepard interpolation is rarely as accurate as the well-tuned application of * other radial basis functions. However, it is simple, fast, and often jut the * thing for quick and dirty applications. * * @author Haifeng Li */ public class ShepardInterpolation1D implements Interpolation { private double[] x; private double[] y; private double p; /** * Constructor. By default p = 2. * @param x the point set. * @param y the function values at given points. */ public ShepardInterpolation1D(double[] x, double[] y) { this(x, y, 2); } /** * Constructor. * @param x the point set. * @param y the function values at given points. * @param p the parameter in the radial basis function φ(r) = r-p. */ public ShepardInterpolation1D(double[] x, double[] y, double p) { this.x = x; this.y = y; this.p = -p; } @Override public double interpolate(double x) { double weight = 0.0, sum = 0.0; for (int i = 0; i < this.x.length; i++) { double r = Math.abs(x - this.x[i]); if (r == 0.0) { return y[i]; } double w = Math.pow(r, p); weight += w; sum += w * y[i]; } return sum / weight; } }

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