Java source code of 'jhplot.math.QRDecomposition'

package jhplot.math;


/**
 * QR Decomposition.
 * 

* For an m-by-n matrix A with m >= n, the QR decomposition is an m-by-n * orthogonal matrix Q and an n-by-n upper triangular matrix R so that A = Q*R. *

* The QR decompostion always exists, even if the matrix does not have full * rank, so the constructor will never fail. The primary use of the QR * decomposition is in the least squares solution of nonsquare systems of * simultaneous linear equations. This will fail if isFullRank() returns false. */ public class QRDecomposition { /* * ------------------------ Class variables ------------------------ */ /** * Array for internal storage of decomposition. * * @serial internal array storage. */ private double[][] QR; /** * Row and column dimensions. * * @serial column dimension. * @serial row dimension. */ private int m, n; /** * Array for internal storage of diagonal of R. * * @serial diagonal of R. */ private double[] Rdiag; /* * ------------------------ Constructor ------------------------ */ /** * QR Decomposition, computed by Householder reflections. * * @param A * Rectangular matrix * @return Structure to access R and the Householder vectors and compute Q. */ public QRDecomposition(double[][] A) { // Initialize. QR = A; m = A.length; n = A[0].length; Rdiag = new double[n]; // Main loop. for (int k = 0; k < n; k++) { // Compute 2-norm of k-th column without under/overflow. double nrm = 0; for (int i = k; i < m; i++) { nrm = Mathfun.hypot(nrm, QR[i][k]); } if (nrm != 0.0) { // Form k-th Householder vector. if (QR[k][k] < 0) { nrm = -nrm; } for (int i = k; i < m; i++) { QR[i][k] /= nrm; } QR[k][k] += 1.0; // Apply transformation to remaining columns. for (int j = k + 1; j < n; j++) { double s = 0.0; for (int i = k; i < m; i++) { s += QR[i][k] * QR[i][j]; } s = -s / QR[k][k]; for (int i = k; i < m; i++) { QR[i][j] += s * QR[i][k]; } } } Rdiag[k] = -nrm; } } /* * ------------------------ Public Methods ------------------------ */ /** * Is the matrix full rank? * * @return true if R, and hence A, has full rank. */ public boolean isFullRank() { for (int j = 0; j < n; j++) { if (Rdiag[j] == 0) return false; } return true; } /** * Return the Householder vectors * * @return Lower trapezoidal matrix whose columns define the reflections */ public double[][] getH() { double[][] X = new double[m][n]; for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { if (i >= j) { X[i][j] = QR[i][j]; } else { X[i][j] = 0.0; } } } return X; } /** * Return the upper triangular factor * * @return R */ public double[][] getR() { double[][] X = new double[n][n]; for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (i < j) { X[i][j] = QR[i][j]; } else if (i == j) { X[i][j] = Rdiag[i]; } else { X[i][j] = 0.0; } } } return X; } /** * Generate and return the (economy-sized) orthogonal factor * * @return Q */ public double[][] getQ() { double[][] X = new double[m][n]; for (int k = n - 1; k >= 0; k--) { for (int i = 0; i < m; i++) { X[i][k] = 0.0; } X[k][k] = 1.0; for (int j = k; j < n; j++) { if (QR[k][k] != 0) { double s = 0.0; for (int i = k; i < m; i++) { s += QR[i][k] * X[i][j]; } s = -s / QR[k][k]; for (int i = k; i < m; i++) { X[i][j] = X[i][j] + s * QR[i][k]; } } } } return X; } /** * Least squares solution of A*X = B * * @param B * A Matrix with as many rows as A and any number of columns. * @return X that minimizes the two norm of Q*R*X-B. * @exception IllegalArgumentException * Matrix row dimensions must agree. * @exception RuntimeException * Matrix is rank deficient. */ public double[][] solve(double[][] B) { if (B.length != m) { throw new IllegalArgumentException("Matrix row dimensions must agree."); } if (!this.isFullRank()) { throw new RuntimeException("Matrix is rank deficient."); } // Copy right hand side int nx = B[0].length; double[][] X = B; // Compute Y = transpose(Q)*B for (int k = 0; k < n; k++) { for (int j = 0; j < nx; j++) { double s = 0.0; for (int i = k; i < m; i++) { s += QR[i][k] * X[i][j]; } s = -s / QR[k][k]; for (int i = k; i < m; i++) { X[i][j] += s * QR[i][k]; } } } // Solve R*X = Y; for (int k = n - 1; k >= 0; k--) { for (int j = 0; j < nx; j++) { X[k][j] /= Rdiag[k]; } for (int i = 0; i < k; i++) { for (int j = 0; j < nx; j++) { X[i][j] -= X[k][j] * QR[i][k]; } } } return DoubleArray.getSubMatrixRangeCopy(X, 0, n - 1, 0, nx - 1); } }