package ca.pfv.spmf.algorithms.sequentialpatterns.lapin;
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.BitSet;
import java.util.Collections;
import java.util.HashMap;
import java.util.HashSet;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
import java.util.Set;
import ca.pfv.spmf.datastructures.triangularmatrix.AbstractTriangularMatrix;
import ca.pfv.spmf.datastructures.triangularmatrix.SparseTriangularMatrix;
import ca.pfv.spmf.input.sequence_database_array_integers.Sequence;
import ca.pfv.spmf.input.sequence_database_array_integers.SequenceDatabase;
import ca.pfv.spmf.tools.MemoryLogger;
/***
* This is an implementation of the LAPIN algorithm (a.k.a LAPIN-SPAM or LAPIN-LCI).
* This implementation tries to be faithful to the original technical report. There is only a minor difference in
* how the I-Step is performed. When an I-step is performed such thats
* the resulting last itemset of the prefix would have 3 or more items, position lists are scanned
* to ensure that only positions where the full itemset appear are considered. In the original LAPIN-SPAM,
* position-lists are instead updated. But because this would be consume too much memory, we took
* the design decision of doing it differently.
*
* The LAPIN-SPAM algorithm was originally described in this paper:
*
* Zhenlu Yang and Masrau Kitsuregawa. LAPIN-SPAM: An improved algorithm for mining sequential pattern
* In Proc. of Int'l Special Workshop on Databases For Next Generation Researchers (SWOD'05)
* in conjunction with ICDE'05, pp. 8-11, Tokyo, Japan, Apr. 2005.
*
* Copyright (c) 2008-2013 Philippe Fournier-Viger
*
* This file is part of the SPMF DATA MINING SOFTWARE
* (http://www.philippe-fournier-viger.com/spmf).
*
* SPMF is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* SPMF is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with SPMF. If not, see > mapItemFirstOccurrences = new HashMap>();
try {
// Read the input file
BufferedReader reader = new BufferedReader(new InputStreamReader(new FileInputStream(new File(input))));
String thisLine;
// for each sequence of the input fiel
while ((thisLine = reader.readLine()) != null) {
// we use a set to remember which item have been seen already
Set itemsAlreadySeen = new HashSet();
// to know the itemset number
short itemsetID = 0;
// for each token in this line
for(String integer: thisLine.split(" ")){
// if it is the end of an itemset
if("-1".equals(integer)){
itemsetID++;
}else if("-2".equals(integer)){ // if it is the end of line
// nothing to do here
}else{
// otherwise, it is an item
Integer item = Integer.valueOf(integer);
// if this item was not seen already in that sequence
if(itemsAlreadySeen.contains(item) == false) {
// Get the list of positions of that item
List list = mapItemFirstOccurrences.get(item);
// if that list is null, create a new list
if(list == null){
list = new ArrayList();
mapItemFirstOccurrences.put(item, list);
}
// Add the position of the item in that sequence to the list of first positions
// of that item
Position position = new Position(sequenceCount, itemsetID);
list.add(position);
// Remember that we have seen this item
itemsAlreadySeen.add(item);
// Check if the item is the largest item until now
if(item > largestItemID) {
largestItemID = item;
}
}
}
}
// Increase the count of sequences from the input file
sequenceCount++;
}
reader.close();
}catch (Exception e) {
e.printStackTrace();
};
// Initialize the list of tables
tables = new Table[sequenceCount];
// Calculate absolute minimum support as a number of sequences
minsup = (int) Math.ceil(minsupRel * sequenceCount);
if(minsup == 0){
minsup = 1;
}
if(DEBUG) {
System.out.println( "Number of items: " + mapItemFirstOccurrences.size());
System.out.println( "Sequence count: " + sequenceCount);
System.out.println( "Abs. minsup: " + minsup + " sequences");
System.out.println( "Rel. minsup: " + minsupRel + " %");
System.out.println("=== Determining the frequent items ===");
}
// // For each frequent item, save it and add it to the list of frequent items
List frequentItems = new ArrayList();
for(Entry> entry : mapItemFirstOccurrences.entrySet()){
// Get the border created by this item
List itemBorder = entry.getValue();
// if the item is frequent
if(itemBorder.size() >= minsup){
// Output the item and add it to the list of frequent items
Integer item = entry.getKey();
savePattern(item, itemBorder.size());
frequentItems.add(item);
if(DEBUG) {
System.out.println(" Item " + item + " is frequent with support = " + itemBorder.size());
}
}
}
if(DEBUG) {
System.out.println("=== Second database scan to construct item-is-exist tables ===");
}
// sort the frequent items (useful when generating 2-IE-sequences, later on).
Collections.sort(frequentItems);
// SECOND DATABASE SCAN:
// Now we will read the database again to create the Item-is-exist-table
// and SE-position-lists and count support of 2-IE-sequences
matrixPairCount = new SparseTriangularMatrix(largestItemID+1);
// Initialise the IE position lists and SE position lists
sePositionList = new SEPositionList[sequenceCount];
iePositionList = new IEPositionList[sequenceCount];
try {
// Prepare to read the file
BufferedReader reader = new BufferedReader(new InputStreamReader(new FileInputStream(new File(input))));
String thisLine;
// For each sequence in the file
int currentSequenceID = 0;
while ((thisLine = reader.readLine()) != null) {
// (1) ------- PARSE THE SEQUENCE BACKWARD TO CREATE THE ITEM-IS-EXIST TABLE FOR THATS SEQUENCE
// AND COUNT THE SUPPORT OF 2-IE-Sequences
// We will also use a structure to remember in which sequence we have seen each pair of items
// Note that in this structure, we will add +1 to the sid because by default the matrix is filled with 0
// and we don't want to think that the first sequence was already seen for all pairs.
AbstractTriangularMatrix matrixPairLastSeenInSID = new SparseTriangularMatrix(largestItemID+1);
// We count the number of positions (number of itemsets).
// To do that we count the number of "-" symbols in the file.
// We need to subtract 1 because the end of line "-2" contains "-".
int positionCount = -1;
for(char caracter : thisLine.toCharArray()) {
if(caracter == '-') {
positionCount++;
}
}
// Now we will scan the sequence again.
// This time we will remember which item were seen already
Set itemsAlreadySeen = new HashSet();
// During this scan, we will create the table for this sequence
Table table = new Table();
// To do that, we first create an initial position vector for that table
BitSet currentBitset = new BitSet(mapItemFirstOccurrences.size()); // OK ?
// This variable will be used to remember if a new item appeared in the current itemset
boolean seenNewItem = false;
// We will scan the sequence backward, starting from the end because
// we should not create a bit vector for all positions but for only
// the positions that are different from the previous one.
String[] tokens = thisLine.split(" ");
// This is the number of itemsets
int currentPosition = positionCount;
// to keep the current itemset in memory
List currentItemset = new ArrayList();
// For each token in that sequence
for(int i = tokens.length-1; i >=0 ; i--){
// get the token
String token = tokens[i];
// if we reached the end of an itemset
if("-1".equals(token)){
// update the triangular matrix for counting 2-IE-sequences
// by comparing each pairs of items in the current itemset
for(int k=0; k < currentItemset.size(); k++) {
Integer item1 = currentItemset.get(k);
for(int m=k+1; m < currentItemset.size(); m++) {
Integer item2 = currentItemset.get(m);
// if that pair is frequent
int sid = matrixPairLastSeenInSID.getSupportForItems(item1, item2);
// and if we have not seen this sequence yet
if(sid != currentSequenceID+1){
// increment support count of this pair
matrixPairCount.incrementCount(item1, item2);
// remember that we have seen this pair so that we don't count it again
matrixPairLastSeenInSID.setSupport(item1, item2, currentSequenceID+1);
}
}
}
currentItemset.clear();
// Decrease the current index of the position (itemset) in the sequence
currentPosition--;
// if the bit vector has changed since previous position, then
// we need to add a new bit vector to the table
if(seenNewItem) {
// create the position vector and add it to the item-is-exist table
PositionVector vector = new PositionVector(currentPosition, (BitSet)currentBitset.clone());
table.add(vector);
}
}else if("-2".equals(token)){ // if end of sequence, nothing to do
}else{
// otherwise, it is an item
Integer item = Integer.valueOf(token);
if(mapItemFirstOccurrences.get(item).size() >= minsup) { // only for frequent items
// if first time that we see this item
if(itemsAlreadySeen.contains(item) == false) {
// remember that we have seen a new item
seenNewItem = true;
// remember that we have seen this item
itemsAlreadySeen.add(item);
// add this item to the current bit vector
currentBitset.set(item);
}
// add this item to the current itemset
currentItemset.add(item);
}
}
}
// Lastly,
// update the triangular matrix for counting 2-IE-sequences one more time
// for the case where the pair is in first position of the sequence
// by considering each pair of items in the last itemset.
// This is done like it was done above, so I will not comment this part of the code again.
for(int k=0; k < currentItemset.size(); k++) {
Integer item1 = currentItemset.get(k);
for(int m=k+1; m < currentItemset.size(); m++) {
Integer item2 = currentItemset.get(m);
// if th
int sid = matrixPairLastSeenInSID.getSupportForItems(item1, item2);
if(sid != currentSequenceID+1){
matrixPairCount.incrementCount(item1, item2);
matrixPairLastSeenInSID.setSupport(item1, item2, currentSequenceID+1);
}
}
}
// If a new item was seen
// Add an extra row to the item-is-exist table that will be called -1 with all items in this sequence
if(seenNewItem) {
PositionVector vector = new PositionVector(-1, (BitSet)currentBitset.clone());
table.add(vector);
}
//
//
// // Initialize the IE lists and SE lists for that sequence
// which will be filled with the next database scan.
sePositionList[currentSequenceID] = new SEPositionList(itemsAlreadySeen);
iePositionList[currentSequenceID] = new IEPositionList();
if(DEBUG) {
System.out.println("Table for sequence " + currentSequenceID + " : " + thisLine);
System.out.println(table.toString());
}
// put the current table in the array of item-is-exist-tables
tables[currentSequenceID] = table;
// we will process the next sequence id
currentSequenceID++;
}
reader.close();
}catch (Exception e) {
e.printStackTrace();
}
// THIRD SCAN TO
// PARSE THE SEQUENCE FORWARD TO CREATE THE SE-POSITION LIST OF THAT SEQUENCE
// AND IEPositionList for frequent 2-IE-SEQUENCES
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(new FileInputStream(new File(input))));
String thisLine;
// For each sequence
int currentSequenceID = 0;
while ((thisLine = reader.readLine()) != null) {
// We will scan the sequence backward, starting from the end.
String[] tokens = thisLine.split(" ");
// to keep the current itemset in memory
List currentItemset = new ArrayList();
// this variable will be used to remember which itemset we are visiting
short itemsetID = 0;
// empty the object to track the current itemset (if it was used for the previous sequence)
currentItemset.clear();
// for each token of the current sequence
for(int i = 0; i < tokens.length; i++){
String token = tokens[i];
// if we reached the end of an itemset
if("-1".equals(token)){
// if the current itemset contains more than one item
if(currentItemset.size() >1) {
// update the position list for 2-IE-sequences
for(int k=0; k < currentItemset.size(); k++) {
Integer item1 = currentItemset.get(k);
for(int m=k+1; m < currentItemset.size(); m++) {
Integer item2 = currentItemset.get(m);
// if the pair is frequent
int support = matrixPairCount.getSupportForItems(item1, item2);
if(support >= minsup){
iePositionList[currentSequenceID].register(item1, item2, itemsetID);
}
}
}
}
// increase itemsetID
itemsetID++;
// clear itemset
currentItemset.clear();
}else if("-2".equals(token)){
// if the end of a sequence, nothing special to do
}else{
// otherwise, the current token is an item
Integer item = Integer.valueOf(token);
// if the item is frequent
if(mapItemFirstOccurrences.get(item).size() >= minsup) {
// we add the current position to the item SE-position list
sePositionList[currentSequenceID].register(item, itemsetID);
// we add the item to the current itemset
currentItemset.add(item);
}
}
}
if(DEBUG) {
System.out.println("SE Position list for sequence " + currentSequenceID );
System.out.println(sePositionList[currentSequenceID]);
System.out.println("IE Position list for sequence " + currentSequenceID );
System.out.println(iePositionList[currentSequenceID]);
}
iePositionList[currentSequenceID].sort(); // sort the IE-position list
// update the sequence id for the next sequence
currentSequenceID++;
}
reader.close();
}catch (Exception e) {
e.printStackTrace();
}
if(DEBUG) {
System.out.println("=== Starting sequential pattern generation ===");
}
// For each frequent item, call the recursive method to explore larger patterns
for(int i=0; i < frequentItems.size(); i++){
// Get the item
int item1 = frequentItems.get(i);
// Get the border for that item
List item1Border = mapItemFirstOccurrences.get(item1);
if(DEBUG) {
System.out.println("=== Considering item " + item1);
System.out.println(" Border of " + item1);
for(Position pos : item1Border) {
System.out.println(" seq: " + pos.sid + " itemset: " + pos.position);
}
}
// if the border contains at least minsup sequence (if the item is frequent)
if(item1Border.size() >= minsup){
// Create an object prefix to represent the sequential pattern containing the item
Prefix prefix = new Prefix();
List itemset = new ArrayList(1);
itemset.add(item1);
prefix.itemsets.add(itemset);
// make a recursive call to find s-extensions of this prefix
genPatterns(prefix, item1Border, frequentItems, frequentItems, item1, true); // true, to disallow I-extension because we explore 2-IE sequences separately
}
// For each frequent 2-IE sequences stating with item1, we will explore 2-IE sequences
// by considering each frequent item larger than item1
for(int k=i+1; k < frequentItems.size(); k++){
// We consider item2
int item2 = frequentItems.get(k);
// Get the support of item1, item2
int support = matrixPairCount.getSupportForItems(item1, item2);
// if the pair {item1, item2} is frequent
if(support >= minsup){
// get the list of position of item2
List item2Border = mapItemFirstOccurrences.get(item2);
// Create the border by using the 2-IE position list
List ie12Border = new ArrayList();
// We will loop over the border of item1 or item2 (the smallest one)
List borderToUse;
if(item2Border.size() < item1Border.size()) {
borderToUse = item2Border;
}else {
borderToUse = item1Border;
}
// For each sequence of the border that we consider
for(Position sequenceToUse : borderToUse) {
// Get the sequence id
int sid = sequenceToUse.sid;
// For this sequence, we will get the position list of each item
List listPosition1 = sePositionList[sid].getListForItem(item1);
List listPosition2 = sePositionList[sid].getListForItem(item2);
// if one of them is null, that means that both item1 and item2 do not appear in that sequence
// so we continue to the next sequence
if(listPosition1 == null || listPosition2 == null) {
continue;
}
// otherwise
// find the first common position of item1 and item2 in the sequence
int index1 = 0;
int index2 = 0;
// we do that by the following while loop
while(index1 < listPosition1.size() && index2 < listPosition2.size()) {
short position1 = listPosition1.get(index1);
short position2 = listPosition2.get(index2);
if(position1 < position2) {
index1++;
}else if(position1 > position2) {
index2++;
}else {
// we have found the position, so we add it to the new border and
// then stop because we do not want to add more than one position for
// the same sequence in the new border
ie12Border.add(new Position(sid, position1));
break;
}
}
}
if(DEBUG) {
System.out.println("=== Considering the 2-IE sequence {" + item1 + "," + item2 + "} with support " + support);
System.out.println(" Border of {" + item1 + "," + item2 + "}");
for(Position pos : ie12Border) {
System.out.println(" seq: " + pos.sid + " itemset: " + pos.position);
}
}
// finally, we create the prefix for the pattern {item1, item2}
Prefix prefix = new Prefix();
List itemset = new ArrayList(2);
itemset.add(item1);
itemset.add(item2);
prefix.itemsets.add(itemset);
// save the pattern
savePattern(prefix, support);
// perform recursive call to extend that pattern
genPatterns(prefix, ie12Border, frequentItems, frequentItems, item2, false); // false, to allow I-extension
}
}
}
// Record the maximum memory usage
MemoryLogger.getInstance().checkMemory();
writer.close();
}
/**
* The main recursive method of LAPIN
* @param prefix the current prefix
* @param prefix the prefix
* @param prefixBorder a list of position that is the prefix border
* @param in items that could be appended by i-extension
* @param sn items that could be appended by s-extension
* @param hasToBeGreaterThanForIStep
* @throws IOException if error while writing to file
*/
private void genPatterns(Prefix prefix, List prefixBorder, List sn, List in, int hasToBeGreaterThanForIStep, boolean doNotPerformIExtensions) throws IOException {
// if(DEBUG) {
// if(seqDB == null) {
// seqDB = new SequenceDatabase();
// seqDB.loadFile(input);
// }
// // FOR DEBUGGING = WORK ONLY FOR SEQUENCE WITH SINGLE ITEMS IN EACH ITEMSET
// System.out.println("Checking if the border of " + prefix + " is correct");
// for(Position pos : prefixBorder) {
// int sid = pos.sid;
// Sequence seq = seqDB.getSequences().get(sid);
// int calculatedPosition = 0;
//
// int prefixItemsetID =0;
// for(; calculatedPosition< seq.size(); calculatedPosition++ ) {
// Integer[] itemset = seq.get(calculatedPosition);
// Integer itemToMatch = prefix.itemsets.get(prefixItemsetID).get(0);
// if(itemset[0].equals(itemToMatch)) {
// prefixItemsetID++;
// if(prefixItemsetID == prefix.size()) {
// if(pos.position != calculatedPosition) {
// System.out.println("THE BORDER IS WRONG FOR PREFIX " + prefix + " AND SEQUENCE :" + sid + " " + seq);
// System.out.println();
// }else {
// System.out.println("THE BORDER IS OK");
// break;
// }
// }
// }
// }
// }
//// }
// ====== S-STEPS ======
// // Temporary variables (as described in the paper)
List sTemp = new ArrayList();
List sTempSupport = new ArrayList();
//
// // for each item in sn
for(Integer item : sn){
// perform the S-STEP
int support = calculateSupportSStep(item, prefixBorder);
// if the support is higher than minsup
if(support >= minsup){
// // record that item and pattern in temporary variables
sTemp.add(item);
sTempSupport.add(support);
}
}
// for each pattern recorded for the s-step
for(int k=0; k < sTemp.size(); k++){
int item = sTemp.get(k);
// create the new prefix
Prefix prefixSStep = prefix.cloneSequence();
List itemset = new ArrayList(1);
itemset.add(item);
prefixSStep.itemsets.add(itemset);
// save the pattern to the file
savePattern(prefixSStep, sTempSupport.get(k));
// recursively try to extend that pattern
List newBorder = recalculateBorderForSExtension(prefixBorder, item);
// Recursive call
genPatterns(prefixSStep, newBorder, sTemp, sTemp, item, false);
}
if(doNotPerformIExtensions) {
return;
}
// ======== I STEPS =======
// Temporary variables
List iTemp = new ArrayList();
List > iTempBorder= new ArrayList>();
//
// // for each item in in
// the item has to be greater than the largest item
// already in the last itemset of prefix.
int index = Collections.binarySearch(in, hasToBeGreaterThanForIStep);
for(int i = index; i< in.size(); i++) {
Integer item = in.get(i);
List lastItemset = prefix.itemsets.get(prefix.itemsets.size() -1);
Integer lastItem = lastItemset.get(lastItemset.size()-1);
boolean willAddSecondItem = lastItemset.size() == 1;
// AN OPTIMIZATION
// perform the I-STEP
int support = estimateSupportIStep(item, prefixBorder);
// if the estimated support is higher than minsup
if(support >= minsup){
// recalculate the border
// in this case, the method takes the prefix border as input
List newBorder = recalculateBorderForIExtension(lastItemset, prefixBorder, hasToBeGreaterThanForIStep, item, willAddSecondItem);
// record that item and pattern in temporary variables
if(newBorder.size() >= minsup) {
iTemp.add(item);
iTempBorder.add(newBorder);
}
}
}
// for each pattern recorded for the i-step
for(int k=0; k < iTemp.size(); k++){
int item = iTemp.get(k);
// create the new prefix
Prefix prefixIStep = prefix.cloneSequence();
prefixIStep.itemsets.get(prefixIStep.size()-1).add(item);
// save the pattern
List newBorder = iTempBorder.get(k);
savePattern(prefixIStep, newBorder.size());
// recursively try to extend that pattern
genPatterns(prefixIStep, newBorder, sTemp, iTemp, item, false);
}
// check the memory usage
MemoryLogger.getInstance().checkMemory();
}
/**
* Recalculate the prefix border following an i-extension
* @param prefixLastItemset last itemset of the previous prefix
* @param prefixBorder the previous prefix border
* @param item1 the last item
* @param item2 the item that will be appended
* @param willAddSecondItem if the item will be added to an itemset containing a single item
* @return the updated border
*/
private List recalculateBorderForIExtension(
List prefixLastItemset, List prefixBorder, int item1, int item2, boolean willAddSecondItem) {
// Create the new border (a list of position)
List newBorder = new ArrayList();
// for each sequence where the prefix appeared
for(Position previousPosition : prefixBorder) {
int sid = previousPosition.sid;
// get where the last two items of the prefix appeared
int previousItemsetID = previousPosition.position;
IEPositionList positionLists = iePositionList[sid];
// find the position that is immediately larger or equal than the current one
// by checking each position in the list of positions for the pair
List listPositions = positionLists.getListForPair(item1, item2);
if(listPositions != null) {
// for each position
loop: for(short pos : listPositions) {
// if the position is larger or equal to the current one
if(pos >= previousItemsetID){
// IMPORTANT:
// if the prefix has two items in its last itemset,
// then we also need to check that the full last itemset of prefix is at the current position
// This will not be done very optimally but it is it difficult to do a better solution.
if(willAddSecondItem == false) {
// We take the SE position list of the current sequence
SEPositionList plists = sePositionList[sid];
// For each item of the last itemset of the prefix
for(int i=0; i< prefixLastItemset.size()-1; i++) {
// We check if that item appears at that position
Integer itemX = prefixLastItemset.get(i);
List plistX = plists.getListForItem(itemX);
int index = Collections.binarySearch(plistX, pos);
// if not, then we stop considering this position
if(index <0) {
continue loop;
}
}
// If the loop has finished, that means that all items from the last itemset of
// the prefix have appeared at the position pos
}
// Then we add the position to the new border
Position newPosition = new Position(sid, pos);
newBorder.add(newPosition);
// After that we will continue to the next sequence to continue creating the new border
break;
}
}
}
}
return newBorder;
}
/**
* Estimate support of appending an item to the current prefix by I-extension
* @param item the item
* @param itemBorder the prefix border
* @return the estimated support (an upper bound)
*/
private int estimateSupportIStep(Integer item, List itemBorder) {
// First we need to take the two last items
int support = 0;
for(Position pos : itemBorder) {
Table table = tables[pos.sid];
int numberOfVectors = table.positionVectors.size();
// Scan from last position to first position (they are ordered backward in the table)
for(int j = 0; j < numberOfVectors; j++) {
PositionVector vector = table.positionVectors.get(j);
if(vector.position < pos.position) {
if(vector.bitset.get(item)) {
support += 1;
}
break;
}
}
}
return support;
}
/**
* Calculate the support of the new prefix resulting from appending an item to the
* prefix by S-extension
* @param item the item
* @param itemBorder the prefix border
* @return the support
*/
private int calculateSupportSStep(Integer item, List itemBorder) {
// Initialize a variable to count the support
int support = 0;
// For each sequence where there is a position in the border
for(Position pos : itemBorder) {
// get the Item-is-exist table corresponding to the sequence
Table table = tables[pos.sid];
// Get the number of vectors in that table
int numberOfVectors = table.positionVectors.size();
// We will scan the vectors to determine if the item appears after the corresponding
// position. If yes, we will increase the support by 1.
// IMPORTANT: We scan the table starting from the last vectors because
// vectors have been inserted in reverse order in the table.
// Also note that we will skip the first vector that has the position -1 because
// this vector was added for i-extension only and should not be considered for s-extension
// Thus, for each vector starting from the second-last one
for(int j = numberOfVectors-2; j>=0; j--) {
// Get the vector
PositionVector vector = table.positionVectors.get(j);
// if the position of this vector is larger or equal to the position that
// we are searching for
if(vector.position >= pos.position) {
// check if the bit corresponding to the item is set to 1
if(vector.bitset.get(item)) {
// if yes, we increase the support by 1
support += 1;
}
// and we don't need to continue looking at the vectors for that sequence
break;
}
}
}
// return the calculated support
return support;
}
/**
* Method to recalculate the border of a prefix after an S-extension with an item
* @param prefixBorder the border of the prefix
* @param item the item used to extend the prefix
* @return the new border
*/
private List recalculateBorderForSExtension(
List prefixBorder, int item) {
// Create a list of position that will be used to store the new bordre
List newBorder = new ArrayList();
// for each sequence where the prefix appeared
for(Position previousPosition : prefixBorder) {
// get the sequence id
int sid = previousPosition.sid;
// get the index of the itemset where the last item of the prefix appeared
int previousItemsetID = previousPosition.position;
// Get the SE position list for the sequence
SEPositionList positionLists = sePositionList[sid];
// Get the list of position for the item for that sequence
List listPositions = positionLists.getListForItem(item);
// if the item appears in that sequence
if(listPositions != null) {
// We check if there is a position where the item appears
// that is after the border.
// For each position
for(short pos : listPositions) {
// if the position is larger
if(pos > previousItemsetID){
// add the position to the new border
Position newPosition = new Position(sid, pos);
newBorder.add(newPosition);
// and stop because we don't want to add more than one position for the same sequence.
break;
}
}
}
}
// return the new border
return newBorder;
}
/**
* Save a pattern that has been found
* @param item the item
* @param support the support of the item
* @throws IOException if error while writing to file
*/
private void savePattern(Integer item, int support) throws IOException {
// increase the number of patterns found
patternCount++;
// create a string buffer to store the string reprensentation of this pattern
StringBuffer r = new StringBuffer("");
// append the item
r.append(item);
// append -1 to indicate the end of the itemset
r.append(" -1 ");
// append its support
r.append("#SUP: ");
r.append(support);
// write the buffer to the output file
writer.write(r.toString());
// create a new line to be ready for writing the next pattern
writer.newLine();
if(DEBUG) {
System.out.println(r.toString());
}
}
/**
* Save a prefix (pattern) to file
* @param prefix the prefix
* @param support the prefix support
* @throws IOException if error ocurrs when writing to file
*/
private void savePattern(Prefix prefix, int support) throws IOException {
// increase the number of patterns found
patternCount++;
// Create a string buffer to store the pattern and its support as a string
StringBuffer r = new StringBuffer("");
// for each itemset
for(List itemset : prefix.itemsets){
// for each item
for(Integer item : itemset){
// append it
String string = item.toString();
r.append(string);
r.append(' ');
}
// at the end of an itemset we put a -1
r.append("-1 ");
}
// then, append the support of the pattern:
r.append("#SUP: ");
r.append(support);
// write the buffer to the output file
writer.write(r.toString());
if(DEBUG) {
System.out.println(r.toString());
}
// create a new line to be ready for the next pattern
writer.newLine();
}
/**
* Print statistics about the algorithm execution time
*/
public void printStatistics() {
StringBuffer r = new StringBuffer(200);
r.append("============= LAPIN - STATISTICS =============\n Total time ~ ");
r.append(endTime - startTime);
r.append(" ms\n");
r.append(" Frequent sequences count : " + patternCount);
r.append('\n');
r.append(" Max memory (mb) : " );
r.append(MemoryLogger.getInstance().getMaxMemory());
r.append(patternCount);
r.append('\n');
r.append("===================================================");
System.out.println(r.toString());
}
/**
* A inner class to store a position (a sequence id + an itemset id). This will be use
* to represent the border of a prefix.
*/
class Position{
/** a sequence id */
int sid;
/** an itemset position in the sequence */
short position;
/**
* Default constructor
* @param sid the sequence id
* @param position the position as a short (itemset number)
*/
public Position(int sid, short position) {
this.sid = sid;
this.position = position;
}
}
}
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